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What is the pH of 0.1 M FeSO4 please show all steps

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Chemistry

What is the pH of 0.1 M FeSO4 please show all steps

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4.0 Ratings (385 Votes)

FeSO4 ------> Fe+2 +SO42-

     SO42- + H2O -----> HSO4- + OH_

I    0.1                         0            0

C   -x                          +X          +x

E   0.1-x                       +x          +x

ka of HSO4- is 0.012

Kb = Kw/ka

     = 1*10-14/0.012

    = 83.3*10-14

Kb = [HSO4-][OH-]/[SO42-]

83.3*10-14 = x*x/0.1-x

x2     = 83.3*10-14

x = 9.12*10-7

[OH-] = x =9.12*10-7 M

POH = -log9.12*10-7

       = -log9.12+7log10

     = -0.9604 +7 = 6.0396

PH = 14-POH

     = 14-6.0396

    = 7.9604
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