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  3. to 1.0 l of a 0.34 m solution of hclo2 is added 0.

To 1.0 L of a 0.34 M solution of HClO2 is added 0.15 mol of...

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Chemistry

To 1.0 L of a 0.34 M solution of HClO2 is added 0.15 mol of NaF.Calculate the [HClO2] at equilibrium.

PLEASE show ALL work!!

Answer & Explanation Solved by verified expert
3.8 Ratings (568 Votes)

no of moles of HClo2 = Molarity * volume in L

                                       = 0.34*1 = 0.34 moles

                      HClO2 + NaF ----------> NaClO2 + H2O

       I                0.34     0.15                      0

      C              -0.15    -0.15                    0.15

      E                0.19       0                        0.15

                [HClO2] = 0.19moles

                [HClO2]   = 0.19/1 = 0.19 M >>>>> answer

                  
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