The reaction NO2 (g) + NO (g) ⇌ N2O (g) + O2 (g) reached equilibrium at...

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Chemistry

The reaction NO2 (g) + NO (g) ⇌ N2O (g) + O2 (g) reachedequilibrium at a certain high temperature. Originally, the reactionvessel contained the following initial concentration: [NO2]i =0.0560 M, [NO]i = 0.294 M, [N2O] = 0.184 M, and [O2] = 0.377 M. Theconcentration of the NO2, the only colored gas in the mixture, wasmonitored by following the intensity of the color. At equilibrium,the NO2 concentration had become 0.118 M. What is the value of Kcfor this reaction at this temperature?

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3.6 Ratings (466 Votes)

                               NO2 (g) +    NO (g)      ⇌      N2O (g)   +    O2 (g)

Initial                     0.056                0.294                   0.184             0.377

at equilibrium        0.056 +x           0.294 +x              0.184-x         0.377-x

So,

equilibrium NO2 concentration = 0.056 +x

But given that equilibrium NO2 concentration = 0.118 M

Hence,

                   0.056 +x = 0.118

                               x = 0.062 M

Hence,

equilibrium concentrations are

[NO2] = 0.118 M

[NO] = 0.294 +x = 0.294 + 0.062 = 0.356 M

[N2O] = 0.184-x = 0.184 -0.062 = 0.122 M

[O2] = 0.377-x = 0.377-0.062 = 0.315 M

Therefore,

     Kc = [ N2O] [O2]/ [NO2] [NO]

            = 0.122 x 0.315 / 0.118 x 0.356

             = 0.912

Therefore,

    Kc = 0.912


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