The numbers of online applications from simple random samples ofcollege applications for 2003 and for the 2009 were taken. In 2003,out of 312 applications, 97 of them were completed online. In 2009,out of 316 applications, 78 of them were completed online. Test theclaim that the proportion of online applications in 2009 was equalto than the proportion of online applications in 2003 at the .10significance level.

Claim: Select an answer u 1 ≤ u 2 u 1 = u 2 p 1 < p 2 u 1< u 2 p 1 ≤ p 2 p 1≠p 2 u 1 > u 2 p 1 = p 2 u 1≠u 2 u 1 ≥ u 2p 1 ≥ p 2 p 1 > p 2  which corresponds to Select ananswer H1: u 1 > u 2 H0: u 1 ≤ u 2 H1: u 1 < u 2 H0: p 1 = p2 H1: p 1 < p 2 H1: p 1 > p 2 H1: u 1≠u 2 H0: p 1 ≤ p 2 H1: p1≠p 2 H0: p 1≠p 2

Opposite: Select an answer u 1 = u 2 p 1 > p 2 u 1 < u 2 p1 ≤ p 2 p 1≠p 2 u 1 ≥ u 2 u 1 ≤ u 2 u 1 > u 2 p 1 ≥ p 2 p 1 = p2 u 1≠u 2 p 1 < p 2  which corresponds to Select ananswer H1: u 1 <= u 2 H0: u 1 > u 2 H1: u 1 ≥ u 2 H0: u 1≠u 2H1: u 1 = u 2 H0: p 1 = p 2 H1: p 1 > p 2 H0: p 1≠p 2 H0: p 1 ≤p 2 H1: p 1≠p 2 H1: p 1 < p 2

The test is: Select an answer /right-tailed / two-tailed /left-tailed

The test statistic is: z = Select an answer 1.79 / 1.95 / 1.47 /2.28 / 2.05  (to 2 decimals)

Based on this we: Fail to reject the null hypothesis / Acceptthe null hypothesis / Reject the null hypothesis / Cannot determineanything

Conclusion There Select an answer (does / does not ) appear to be enough evidence tosupport the claim that the proportion of online applications in2009 was equal to than the proportion of online applications in2003.

The critical value is: z a/ 2= ±± Select an answer / 1.64 / 1.44/ 1.64 / 1.28 / 1.15  (to 2 decimals)