Cumene, a hydrocarbon, is 89.94% carbon, and its molar mass is 120.2 g/mol. What are the a) empirical and...

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Chemistry

Cumene, a hydrocarbon,is 89.94% carbon, and its molar mass is 120.2 g/mol.

What are the

a)empirical and b) molecularformulas for Cumene? Show your work

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4.3 Ratings (920 Votes)

C%   = 89.94%

H%    = 100-C%

          = 100-89.94

            = 10.06%

Element           %                 A.Wt               Relative numer           simple ratio      simplest ratio

C                  89.94                 12                89.94/12 = 7.495           7.495/7.495 = 1          1*3 = 3

H                 10.06                   1              10.06 /1 = 10.06           10.06/7.495 = 1.342      1.342*3 = 4

               The empirical formula   = C3H4

            Empirical formula mass   = 40g/mole

           molar mass = 120.2 g/mol.

                molecular formula     = (empirical formula)n

                                    n       = molar mass/empirical formula mass

                                              = 120.2/40   = 3

molecular formula   = (C3H4)3   = C9H12


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