Â
Br2(g) + F2(g) ⇔ 2 BrF(g)
IÂ Â Â Â Â Â Â Â
0.121Â Â Â
0.121Â Â Â Â Â Â Â Â 0
CÂ Â Â Â Â Â Â Â
-x       Â
-x           Â
2x
E    0.121-x Â
0.121-x   2x
     Kc  =
[BrF]2/[Br2][F2]
   54.7   = (2x)2
/(0.121-x)(0.121-x)
   54.7  =
(2x/0.121-x)2
   7.34  = 2x/0.121-x
    2x    =
7.34(0.121-x)
    x = 0.095
  [F2] = 0.121-x = 0.121-0.095 = 0.026M
[Br2] = 0.121-x = 0.121-0.095 = 0.026M
  [BrF]  = 2x =
2*0.095Â Â Â Â Â Â Â Â Â Â Â Â Â
= 0.19M
