Swannamotosis is a variant of Neurofibromatosis-type 2. It is an autosomal dominant condition that shows both...

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Biology

Swannamotosis is a variant of Neurofibromatosis-type 2. It is anautosomal dominant condition that shows both incomplete penetranceand variable expressivity. Sixty percent of individuals with atleast one mutant allele will show the condition in the phenotype.Of those showing the phenotype, 20% have a severe version, 50% havea moderate version, and 30% have a mild version. If twoheterozygous parents have a child, what is the chance that is willshow the most severe form of the disorder? To calculate this we'llhave to multiply ___ X X X _. If achild of two heterozygous parents, does not have the condition,what is their chance that they do NOT have the allele? ______
Blank 1 Options: 1/2, 1/4, 2/3, 3/4, 1
Blank 2 Options: 0.4, 0.6, I dont need either of thesevalues
Blank 3 Options: 0.2, 0.3, 0.5, I dont need any of thesevalues
Blank 4 Options: 1/4, 1/2, 2/3, 3/4, I dont need any of thesevalues
Blank 5 Options: 1/4 x 0.4 x 0.2, 2/3 x 0.4, 1/4 x 0.4(3.4),(1/4)/(0.4 x (3/4)), (1/4)/((1/4) + 0.4(3.4))

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4.0 Ratings (523 Votes)

It is given that the Swannamotosis is an autosomal dominant condition so presence of even one dominant allele will cause the condition Parents are heterozygous For parents See Answer

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