SHOW ALL WORK 1) The air pollutant NO is produced in automobile engines from the high-temperature reaction,...

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Chemistry

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1) The air pollutant NO is produced in automobile engines fromthe high-temperature reaction, N2 (g) + O2 (g) ⇌ 2 NO (g); Kc = 1.7× 10-3 at 2300K . If the initial concentrations of N2 and O2 at2300 K are both 1.4 M, what are the concentrations of NO, N2, andO2 when the reaction mixture reaches equilibrium? Show your work(20 points).

2) For each of the following equilibria, use LeChatelier’sprinciple to predict the direction of reaction when the volume isincreased. (15 points)

(a) CO(g) + H2(g) ⇌ C(s) + H2O(g)

(b) 2H2(g) + O2 (g) ⇌ 2 H2O(g)

(c) Fe2O3(s) + 3 H2(g) ⇌ 2Fe(s) + 3 H2O(g)

3) Will the concentration of NO2 increase, decrease, or remainthe same when the equilibrium of the exothermic reaction, NOCl(g) +NO2(g) ⇌ NO2Cl (g) + NO(g) is disturbed by the following changes?(15 points)

(a) adding NOCl

(b) adding NO

(c) Removing NO

(d) Adding argon

(e) addition of a catalyst

4) Calculate [H+] of a solution prepared by dissolving 4.25grams of lithium hydroxide (24 g/mole) in water (18 g/mole) to give350.0 mL of solution. (12 points) Kw= 1.0 × 10-14

5) Lactic acid (C3H6O3), whichoccurs in sour milk and foods such as sauerkraut, is a weakmonoprotic acid. The [H+] of a 0.10 M solution of lactic acid is4.57 × 10-3. What is the value of Ka for lactic acid? (16points)

6) Write a chemical reaction foreach of the following ions reacting with water. Demonstrate withthis reaction whether they give neutral, acidic, or a basicsolution. (16 points)

(a) F-

(c) NH4+

(d) K(H2O)6+

(e) SO32-

7) Calculate the percentdissociation of 0.10 M hydrazoic acid (HN3; Ka = 1.9 ×10-5) in thepresence of 0.10 M HCl, and explain if this dissociation is more,the same, or less than if the HCl was not present. (16points)

Answer & Explanation Solved by verified expert
4.0 Ratings (653 Votes)
1 We write the reaction as N2 g O2 g 2 NO g The equilibrium constant for the reaction is Kc NO2N2O2 The equilibrium constant is constant at a particular temperature the concentrations are supplied in molesliter We shall use the ICE table to calculate the equilibrium concentrations of all the species N2 O2 2 NO initial 14 14 0 change x x 2x equilibrium 14x 14x 02x We substitute the values in the equation for Kc Kc 2x214x14x or 17 x 103 4x2 14 x2 Taking positive square root on both sides we have 00412 2x14x or x 00282 Therefore the equilibrium concentrations are N2 14 00282 13718 M O2 14 00282 13718 M NO 2 X 00282 00564 M ans 2a When the volume of a system is increased at equilibrium the system will adjust in such a way so as to nullify the effect of the change    See Answer
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