QUESTION 1 A sample of weights of 50 boxes of cereal yield a sample average of 17...

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QUESTION 1


A sample of weights of 50 boxes of cereal yield a sample average of17 ounces. What would be the margin of error for a 90% CI of theaverage weight of all such boxes if the population deviation is0.48 ounces?

Round to the nearest hundredth

QUESTION 2



A sample of heights of 117 American men yields a sample average of57.04 inches. What would be the margin of error for a 95.44% CI ofthe average height of all such men if the population deviation is3.8 inches?

Round to the nearest hundredth

QUESTION 3



A sample of weights of 37 boxes of cereal yield a sample average of17.8 ounces. What would be the margin of error for a 95% CI of theaverage weight of all such boxes if the population deviation is0.35 ounces?

Round to the nearest hundredth

QUESTION 4



A sample of weights of 25 boxes of cereal yield a sample average of16.5 ounces. What would be the margin of error for a 96% CI of theaverage weight of all such boxes if the sample deviation is 0.73ounces?

The population of all such weights is normally distributed.

Round to the nearest hundredth

QUESTION 5

:

A confidence interval is to be found using a sample of size 676 andthe sample deviation of 5.89.

If the critical value should be a z-score, type the number 0below
If the critical value should be a t-score, type the number 1below

*The computer is looking for either the input 0 or the input 1. Itwill not recognize anything else you type in

Answer & Explanation Solved by verified expert
4.1 Ratings (626 Votes)
1 sample mean xbar 17 sample standard deviation 048 sample size n 50 Given CI level is 90 hence 1 09 01 2 012 005 Zc Z2 164 ME zc sqrtn ME 164    See Answer
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