Just as pHpH is the negative logarithm of [H3O+][H3O+], pKapKa is the negative logarithm of KaKa pKa=−logKapKa=−log⁡Ka The...

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Chemistry

Just as pHpH is the negative logarithm of [H3O+][H3O+], pKapKais the negative logarithm of KaKa

pKa=−logKapKa=−log⁡Ka

The Henderson-Hasselbalch equation is used to calculate the pHpHof buffer solutions:

pH=pKa+log[base][acid]pH=pKa+log⁡[base][acid]

Notice that the pHpH of a buffer has a value close to the pKapKaof the acid, differing only by the logarithm of the concentrationratio [base]/[acid][base]/[acid]. The Henderson-Hasselbalchequation in terms of pOH and pKbpKb is similar.

pOH=pKb+log[acid][base]

How many grams of dry NH4ClNH4Cl need to be added to 1.80 LL ofa 0.100 MM solution of ammonia, NH3NH3, to prepare a buffersolution that has a pHpH of 8.85? KbKb 1.8×10−51.8×10−5.

Express your answer with the appropriate units.

Answer & Explanation Solved by verified expert
3.8 Ratings (531 Votes)
Using eqn 1 and eqn 2moles of NH40180 mol 257moles of NH4 257    See Answer
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