If f(x)=2x^2−5x+3, find f'(−4).      Use this to find the equation of the tangent line to the parabola y=2x^2−5x+3...

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If f(x)=2x^2−5x+3, findf'(−4).     

Use this to find the equation of the tangent line to the parabolay=2x^2−5x+3 at the point (−4,55). The equation of this tangent linecan be written in the form y=mx+b
where m is: ????


and where b is: ????

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