if a 4.000gram sample potassium acid phthalate is equivalent to 48.37 ml of a sodium hydroxide...

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if a 4.000gram sample potassium acid phthalate is equivalent to48.37 ml of a sodium hydroxide solution, what is the concentrationof the latter?

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The molecular formula of is â€Žpotassium acid phthalate C₈H₅KO₄

Molar mass of potassium acid phthalate is 204 g/mol

So number of moles of potassium acid phthalate , n = mass/molar mass

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 4.000 g / 204 (g/mol)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.0196 mol

Which is equivalent to 48.37 ml of NaOH

So Molarity of NaOH ,M = number of moles / volume in L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.0196 mol / ( 48.37/1000) L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.405 M

Therefore the molarity of NaOH is 0.405 M

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