If 3/(2+ cos θ+i sin θ) = a+ib, then [(a-2)2+b2] is

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If 3/(2+ cos θ+i sin θ) = a+ib, then [(a-2)2+b2] is

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Given 32 cos i sin aib 3 2 cos i sin 2 cos i sin 2cos i sin 6 3 cos i 3 sin    See Answer
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