Friction Experiment Procedure: On the pulley place 50 grams weight on the block which is 0.05kg Attach the wood...

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Physics

Friction Experiment
Procedure:
On the pulley place 50 grams weight on the block which is0.05kg
Attach the wood block using a string and hanger
Place the hanger on the other side of the pulley
Use additional weight and put them on the hanger in order toachieve a constant velocity
Data A:
M1
M2
N
Fnet
mu
.17 N
.05 N
1.7 N
0.5
0.30
.22 N
.055 N
2.2 N
0.55
0.25
.27 N
.07 N
2.7 N
0.7
0.26
.32 N
.07 N
3.2 N
0.7
0.22
.37 N
.09 N
3.7 N
0.9
0.24
Procedure:
Place 50 grams on top of the wood block and 50 grams on thehanger and observe acceleration. Use additional weight ifnecessary
Record the time for the motion
Calculate experimental acceleration
Calculate theoretical acceleration
Compare using percent error formula
Repeat one more time
Formulas A:
M1= Mw+n*50 (n is an integer, start with n=1, go to n=4)
N=M1 g
Fnet= M2 g
Mu= Fnet/N
Data B:
Distance
Time
A(experiment)
MI(N)
M2
A(theory)
%Difference
.5 m
.93 s
1.2 m/s^2
.12 N
.1 N
3.18 m/s^2
62.3%
.5 m
.64 s
.61 m/s^2
.17 N
.1 N
2.13 m/s^2
71.8%
Formulas B:
A(experiment)= 2d/t^2
Average mu= 0.25 --> mu=0.25 for equation below
A(theory)= (M2 g- mu M1 g)/(M1+M2)
Question: I'm looking for the formulas worked out forboth data tables
ex: plugging in what numbers into what equation to getanswers from both data tables?

Answer & Explanation Solved by verified expert

4.4 Ratings (951 Votes)

The diagram of experiment is approximately as shown belowAThere are two forces acting on the string In experiment 1 aconstant velocity is achieved so See Answer

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M1	M2	N	Fnet	mu
.17 N	.05 N	1.7 N	0.5	0.30
.22 N	.055 N	2.2 N	0.55	0.25
.27 N	.07 N	2.7 N	0.7	0.26
.32 N	.07 N	3.2 N	0.7	0.22
.37 N	.09 N	3.7 N	0.9	0.24

Distance	Time	A(experiment)	MI(N)	M2	A(theory)	%Difference
.5 m	.93 s	1.2 m/s^2	.12 N	.1 N	3.18 m/s^2	62.3%
.5 m	.64 s	.61 m/s^2	.17 N	.1 N	2.13 m/s^2	71.8%