solve for matrix B Let I be Identity matrix (I-2B)-1= 1 -3 3 -2 2 -5 3 -8 9

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Advance Math

solve for matrix B

Let I be Identity matrix

(I-2B)-1=

1-33
-22-5
3-89

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3.7 Ratings (574 Votes)
Matrix I is A1 A2 A3 1 1 0 0 2 0 1 0 3 0 0 1 Matrix 2B is B1 B2 B3 1 1 6 6 2 4 4 10 3 6 16 18 now on subtracting 2B from I we get following matrix C1 C2 C3 1 0 6 6 2 4 3 10 3 6 16 17 now we have find inverse of above matrix Your matrix is A1 A2 A3 1 0 6 6 2 4 3 10 3 6 16 17 Determinant is not zero therefore inverse matrix exists Write the augmented matrix A1 A2 A3 B1 B2 B3 1 0 6 6 1 0 0 2 4 3 10 0 1 0 3 6 16 17 0 0 1 Make the pivot in the 1st column by dividing the 2nd row by 4 and swap the 2nd and the 2nd rows A1 A2 A3 B1 B2 B3 1 1 075 25 0 025 0 2 0 6 6 1 0 0 3 6 16 17 0 0 1 Multiply the 1st row by 6 A1 A2 A3 B1 B2 B3    See Answer
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