Â
SO3(g)Â Â Â Â Â +Â Â
  H2O(l)
=Â Â Â Â Â Â Â
H2SO4(aq)
Moles     Â
61.5/80Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
11.2/18
            Â
=
0.76875Â Â Â Â Â Â Â Â Â Â Â Â Â Â
= 0.622Â Â Â Â Â
Water is limiting reagnet so all caluclations should be
according to water
expected moles of H2SO4(aq) formed = 0.622
moles
Mass of  H2SO4(aq)
formed   = 0.622x98 = 60.9 75 gram ( theoretical
yield)
% yield = (actual mass formed/expected mass )x100 = ( 51.0g/60.9
75)x100 = 83.64 %
