At 2:00 p.m. a car's speedometer reads 30 mi/h. At 2:10 p.m. it reads 50...
80.2K
Verified Solution
Link Copied!
Question
Calculus
At 2:00 p.m. a car's speedometer reads 30 mi/h. At 2:10 p.m. it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acceleration is exactly 120 mi/h.Let v(t) be the velocity of the car t hours after 2:00 p.m. Then [v(1/6) - v(0)] / (1/6 - 0) = By the Mean Value Theorem, there is a number c such that 0 < c < with v'(c) = Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 p.m. is exactly 120 mi/h.
Answer & Explanation
Solved by verified expert
Get Answers to Unlimited Questions
Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!
Membership Benefits:
Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Zin AI - Your personal assistant for all your inquiries!
