Assume that the mean of the engineered part is 79.95 and
standard deviation of 0.017291, with...
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General Management
Assume that the mean of the engineered part is 79.95 andstandard deviation of 0.017291, with a lower specification limit of79.9 and upper specification limit of 80.
a. Determine the probability that a part is defective.
b. Suppose that 1,000,000 parts are produced, what is theexpected number of defective units? This is equivalent to findingthe PPM (parts per million).
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3.6 Ratings (475 Votes)
Following are the given data Upper specification Limit USL 80 Lower specification Limit LSL 799 Mean of engineering part m 7995 Standard deviation of engineering part Sd 0017291 Let z value corresponding to probability that
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