An unknown compound contains only C, H, and O. Combustion of 6.10 g of this compound...

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Chemistry

An unknown compound contains only C, H, and O. Combustion of6.10 g of this compound produced 14.9 g of CO2 and 6.10 g of H2O.What is the empirical formula of the unknown compound?

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4.3 Ratings (550 Votes)

C%Â Â Â Â Â =Â Â 12*wt of CO2*100/44*wt of organic compound

Â Â Â Â Â Â Â Â Â Â Â = 12*14.9*100/44*6.1Â Â = 66.62%

H%Â Â Â = 2*wt of H2O*100/18*wt of organic compound

Â Â Â Â Â Â Â Â Â = 2*6.1*100/18*6.1Â Â = 11.11%

O%Â Â Â Â Â = 100-(C% +H%)

Â Â Â Â Â Â Â Â Â Â Â = 100-(66.62+11.11)Â Â = 22.27%

ElementÂ Â Â Â Â Â Â Â Â Â Â %Â Â Â Â Â Â Â Â Â Â Â A.WtÂ Â Â Â Â Â Â Â Â Relative numberÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â simple ratio

CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 66.62Â Â Â Â Â Â Â Â Â Â Â 12Â Â Â Â Â Â Â Â Â Â Â Â Â Â 66.62/12= 5.55Â Â Â Â Â Â Â Â Â Â Â Â Â 5.55/1.39Â Â = 4

HÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 11.11Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 11.11/1Â Â = 11.11Â Â Â Â Â Â Â Â Â 11.11/1.39Â Â = 8

OÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â 22.27Â Â Â Â Â Â Â Â Â Â Â Â Â 16Â Â Â Â Â Â Â Â Â Â Â Â Â Â 22.27/16Â Â = 1.39Â Â Â Â Â Â Â Â Â 1.39/1.39 = 1

Â Â Empirical formulaÂ Â = C4H8O

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