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An attacker at the base of a castle wall 3.75 m high throws a rock straight...

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Question

Physics

An attacker at the base of a castle wall 3.75 m high throws arock straight up with speed 8.50 m/s from a height of 1.60 m abovethe ground.

(a) what is the rock speed at the top? ?

m/s

(b) Find the change in speed of a rock thrown straight down fromthe top of the wall at an initial speed of 8.50 m/s and movingbetween the same two points.

?m/s

(c) Does the change in speed of the downward-moving rock agreewith the magnitude of the speed change of the rock moving upwardbetween the same elevations? Explain physically why it does or doesnot agree.

Answer & Explanation Solved by verified expert
4.0 Ratings (560 Votes)
a Use the kinematic formula Vf2 Vi2 2ay where Vf 0 it comes to a stop at the highest point Vi 850 ms a g 98 ms2 negative because the 850 ms is up and gravity acts downward y the height at which Vf is zero    See Answer
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