The laser sight Jupiter uses for surveying is a littleoff. The mean error is 0.29m, meaning that it tends to providemeasurements that are 0.29m too long. The standard deviation of theerrors is 0.35m. She decides to recalibrate the device, but shewants to test it afterward to see if she made things better orworse. She collects a random sample of 43 measurements of a 100mdistance. a) Identify the population of interest. b)Identify the variable of interest. What type of variable isit? c) ???????If she measured the 100m distanceBEFORE recalibrating, what would the mean of the measurements havebeen? d) ???????If she wishes to assess how faroff the sight is AFTER recalibrating, what parameter should sheestimate? Mean error ? Std. Error .0676? e)???????Are the conditions for estimating the parameter youchose in part d met? What assumptions would you need to make?f)?????? Estimate the parameter you chose in partd with 99% confidence. Does her recalibration appear to haveimproved this situation? g)??????? If she wishesto assess how reliable the sight is AFTER recalibrating, whatparameter should she estimate? h) ???????Are theconditions for estimating the parameter you chose in part g met?What assumptions would you need to make?i)?????Estimate the parameter you chose in part gwith 99% confidence. Does her recalibration appear to have improvedthis situation? j)??????? Overall, do you thinkher recalibration made things better or worse?
sample data:
99.87 |
100.17 |
100.9 |
100.65 |
99.84 |
100.59 |
99.62 |
99.09 |
99.43 |
100.13 |
99.74 |
99.21 |
100.3 |
99.98 |
100.37 |
100.18 |
99.83 |
100.34 |
100.3 |
100.1 |
100.11 |
99.47 |
100.48 |
101.05 |
99.61 |
99.93 |
100.74 |
99.99 |
100.06 |
100.55 |
99.85 |
99.73 |
99.93 |
100.6 |
99.89 |
100.37 |
99.78 |
100.89 |
100.29 |
99.91 |
100.42 |
100.11 |
99.66 |