An administrator wanted to study the utilization of long-distance telephone service by a department. One variable...

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Statistics

An administrator wanted to study the utilization oflong-distance telephone service by a department. One variable ofinterest (let’s call it X) is the length, in minutes, oflong-distance calls made during one month. There were 38 calls thatresulted in a connection. The length of calls, already ordered fromsmallest to largest, are presented in the followingtable.

1.6

1.7

1.8

1.8

1.9

2.1

2.5

3.0

3.0

4.4

4.5

4.5

5.9

7.1

7.4

7.5

7.7

8.6

9.3

9.5

12.7

15.3

15.5

15.9

15.9

16.1

16.5

17.3

17.5

19.0

19.4

22.5

23.5

24.0

31.7

32.8

43.5

53.3

Which one of the following statements is nottrue?

  1. The 75th percentile (Q3) is 17.5 minutes.

  2. The 50th percentile is (Q2) 9.4 minutes.

  3. The 25th percentile (Q1) is 4.4 minutes.

  4. Q3- Q2 > Q2- Q1

  5. Average X > Median X.

  6. X distribution is positively skewed.

  7. The percentile rank of 5.9 minutes is 13.

  8. Range of X is 51.7 minutes.

  9. IQR (Inter-Quartile Range) is 13.1 minutes.

  10. There are 2 outliers in X distribution.

Q4: (This continues Q3: 2 marks) Which one of thefollowing cannot be used to describe the distribution ofX?

  1. A Histogram.

  2. A Stemplot.

  3. Skewness and Kurtosis.

  4. Mean and SD (Standard Deviation).

  5. The 5-number Summary.

  6. The coefficient of determination.

  7. The coefficient of relative variation(CRV).

  8. The 1.5 IQR Rule.

  9. The Deciles.

  10. A Boxplot.

Answer & Explanation Solved by verified expert
3.9 Ratings (485 Votes)
An administrator wanted to study the utilization oflongdistance telephone service by a departmentOne variable of interest lets call it X is the length inminutes of longdistance calls made during one monthThe length of calls already ordered from smallest to largestare presented in the following table1617181819212530304445455971747577869395127153155159159161165173175190194225235240317328435533Which one of the following statements is not trueNow we will find each of the required quantity to justifyweather statements is not trueiThe 75th percentile Q3 is 175 minutesGiven sample size 38 even Thus 75th percentile for even data with n 38is given byTo calculate 75th percentile we will first calculate Median ofdataMedian n2th observation n21th observation 2 382th observation 3821th observation 2 19th observation 20th observation 2From given dat data is 19th observation 93 and20th observation 95Thus Median 93 95 2 188 2 94Thus Median 94Now 75th percentile is nothing but median of data whichis more that Median value ieMedian of this observation medain value 94 soobservation greater than 94 are 95 127 153 155 159 159 161 165 173175 190 194 225 235 240 317 328 435533Number of observation greater than 94 are n3 19 odd Median of odd number is given byMedian of data greater than 94 n3 1    See Answer
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