A wastewater plant with the activated sludge process received 5 × 106 L/day of wastewater with...

70.2K

Verified Solution

Question

Civil Engineering

  1. A wastewater plant with the activated sludge process received 5× 106 L/day of wastewater with a BOD5 of 500mg/L. The primary clarifier removes 30% of the BOD and primaryclarify effluent has no biomass (Xi=0 mg/L). Recycle(Qr) and waste sludge (Qw) flows are 25% and2% of Qin, respectively. Effluent BOD5 from secondaryclarifier and waste sludge is 20 mg/L. Microorganism concentrationin the waste sludge (Xw) is 6,000 mg/L. SolubleBOD5 is biologically converted into CO2 and Y(yield coefficient) is 0.5 mgVSS /mgBOD
    1. Calculate the value of X and the volume of the tank

Answer & Explanation Solved by verified expert
4.1 Ratings (853 Votes)
    See Answer
Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students