A symmetrical table of height 0.750 m, length 1.55 m, and weight 462 N is dragged...

50.1K

Verified Solution

Question

Physics

A symmetrical table of height 0.750 m, length 1.55 m, and weight462 N is dragged across the floor by a force applied to its frontedge. The force is directed to the right and upward and makes anangle of 30.0Â° with the horizontal.
(a) Find the minimum force necessary to drag the table acrossthe floor. The coefficient of sliding friction between table andfloor is 0.375. 164.45 N
Â Â

(b) Calculate the normal force and the frictional force on eachleg.
front legs:Â Â normal force
frictional force
back legs: normal force
frictional force

Answer & Explanation Solved by verified expert

4.0 Ratings (830 Votes)

a let the force needed is F in vertical direction N is the normal force 462 F sin30 N for the force in horizontal direction F cos30 u N F cos30 0375 462 F See Answer

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member

front legs:Â Â	normal force
	frictional force
back legs:	normal force
	frictional force