A radio station runs a promotion at an auto show with a money box with 14...

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A radio station runs a promotion at an auto show with a moneybox with 14 â€‹$50 â€‹tickets, 10 â€‹$25 â€‹tickets, and 15 â€‹$5 tickets.The box contains an additional 20 â€‹\"dummy\" tickets with no value.Three tickets are randomly drawn. Find the probability that allthree tickets have no value. The probability that all three ticketsdrawn have no money value is nothing. â€‹(Round to four decimalplaces asâ€‹ needed.)

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Total tickets = 14 + 10 + 15 + 20 = 59

P(all 3 tickets have no value) = 20C3 / 59C3 = 1140 / 32509 = 0.0351 (ans)

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