A particle moves in the xy plane with constant
acceleration. At t = 0 the particle...
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Physics
A particle moves in the xy plane with constantacceleration. At t = 0 the particle is at r1 =(4.0 m) + (3.0 m), with velocity 1. At t = 3 s,the particle has moved to r2 = (9 m) − (2.0 m) and itsvelocity has changed to v2 = (5.0 m/s) − (6.0 m/s).
i. Find 1 = m/s
ii. What is the acceleration of the particle?
iii. What is the velocity of the particle as a function oftime?
iv. What is the position vector of the particle as a function oftime?
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4.3 Ratings (625 Votes)
given initial position final postion time interval t 3sfinal
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