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  3. a gaseous mixture consists of 76.0 mole percent n2

A gaseous mixture consists of 76.0 mole percent N2 and 24.0 mole percent O2 (the approximate composition...

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Chemistry

A gaseous mixture consists of 76.0 mole percentN2 and 24.0 mole percent O2(the approximate composition of air). Suppose water is saturatedwith the gas mixture at 25°C and 1.00 atm total pressure, and thenthe gas is expelled from the water by heating. What is thecomposition in mole fractions of the gas mixture that is expelled?The solubilities of N2 and O2at 25°C and 1.00atm are 0.0175 g/L H2O and 0.0393 g/L H2O,respectively.

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4.1 Ratings (812 Votes)

The solubilities of N2 = 0.0175 g/L

molarity of N2 = 0.0175 / 28 = 0.000625

moles = molarity x volume

volume = 1 L

so moles = molarity

moles of N2 = 0.000625

The solubilities of O2 = 0.0393 g/L

molarity of O2 = 0.0393 / 32 = 0.00123

moles of O2 = 0.00123

total moles = moles of N2 + moles of O2 = 0.000625 + 0.00123

                  = 0.001855

mole fraction of N2 = moles of N2 / total moles

                               = 0.000625 / 0.001855

                               = 0.3369

compostion of N2 = 33.69%

mole fraction of O2 = 0.6631

composition of O2 = 66.31%
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