A buffet restaurant uses heat lamps at a temperature of 50oC to keep the food warm....

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Biology

A buffet restaurant uses heat lamps at a temperature of50oC to keep the food warm. If the restaurant opens forservice at 4 pm and closes at 10 pm, some of the food items thatare not refilled frequently may sit for 6 hours at thistemperature.

The following experiment was conducted to determine whether thistemperature is suitable to maintain the food and prevent bacterialgrowth:

Beef cubes were inoculated with500,000 bacterial cells and incubated at 43-53oC toestablish temperature limits for bacterial growth. Table 1 containsthe numbers of bacteria after incubation for 6 hours, and platingon nutrient agar given in the numbers of colonies for a particulardilution.

Calculate the cfu/ml for each organismat each temperature using the formula

cfu/ml = # colonies x dilution factorx plating factor (10)

(this is what i mostly need help with,how does one calculate the plating factor? or am i just suppose tothink 10 is the plating factor and multiple the previous numbers by10?)

and draw a line or bar graph toindicate the amount of growth after 6 hours for eachtemperature.

What holding temperature would you recommend to maintain thefood with minimal contamination? Is 50oC sufficient?Assuming that cooking kills bacteria in food, how could thesebacteria contaminate the cooked foods? What disease does eachorganism

Organism

Temp.(oC)

# Colonies

Dilution

Staphylococcus aureus

43

15

1:1000000

51

8

1:10000

53

6

1:100

Salmonella typhimurium

43

32

1:100000

51

9

1:10000

53

2

1:1000

Clostridium perfringens

43

17

1:100000

51

12

1:1000

53

4

1:100

Answer & Explanation Solved by verified expert
3.7 Ratings (435 Votes)
Organism Temp 0C of colonies Dilution Dilution factor Cfuml Staphylococcus aureus 41 15 11000000 106 1510610 15 X 108 51 8 110000 104 810410 8 X 105 53 6 1100 102 610210 6 X 103 Salmonella typhimurium 41 32 110000 105 3210510 32 X 107 51 9 110000 104 910410 9 X 105 53 12 11000 103 1210310 12 X 105 Clostridium perfringens 41 17 1100000    See Answer
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