A 8.6-kg cube of copper (cCu = 386 J/kg-K) has a temperature of 750 K. It...

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Physics

A 8.6-kg cube of copper (cCu = 386 J/kg-K) has atemperature of 750 K. It is dropped into a bucket containing 5.1 kgof water (cwater = 4186 J/kg-K) with an initialtemperature of 293 K.

1)

What is the final temperature of the water-and-cube system?

K

2)

If the temperature of the copper was instead 1350 K, it wouldcause the water to boil. How much liquid water (latent heat ofvaporization = 2.26 × 106 J/kg) will be left after thewater stops boiling?

kg

3)

Let's try this again, but this time add just the minimum amountof water needed to lower the temperature of the copper to 373 K. Inother words, we start with the cube of copper at 750 K and we onlyadd enough water at 293 K so that it completely evaporates by thetime the copper reaches 373 K. Assume the resulting water vaporremaining at 373 K. How much water do we need ?

kg

Answer & Explanation Solved by verified expert
3.7 Ratings (718 Votes)
Question 1 Since its in equilibrium Qcopper Qwater mCucCudeltaT mwatercwaterdeltaT 84386x750 514186x293 32424x 2431800 213486x 6255132 3242x 2431800 213486x 6255132 8686932 246266x x 35274K Final Temp Question 2 First start by finding the amount of energy needed to raise the water from 293    See Answer
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