A 7.95-atm PCl5 is initially placed in an empty vessel at 25ËšC. Calculate Kp if the...

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Chemistry

A 7.95-atm PCl₅ is initially placed in an emptyvessel at 25ËšC. Calculate K_p if the equilibrium partialpressure of Cl₂ is 3.00 atm at the same temperature.
I am completely lost on how to even start the problem, let alonesolve it.

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3.7 Ratings (297 Votes)

PCl5Â Â <--------------------------> PCl3 + Cl2

7.95Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â ----------------------> initial pressure

-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â +xÂ Â Â Â -----------------------> changed pressure

7.95 - xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â xÂ Â Â Â Â Â Â xÂ Â Â ------------------------> equilibrium pressure

from data equilibrium pressure of Cl2 is given . that means x is given

x= 3 atm

now equilibirum pressure of all components

PCl5 partial pressure = 7.95 -x = 7.95 -3 = 4.95 atm

PCl3 partial pressureÂ Â = x = 3 atm

Cl2 partial pressureÂ Â = x = 3 atm

now equilibrium constant Kp

Kp = P_PCl3 x P_Cl2 / P_PCl5

Kp = 3 x 3 / 4.95

Kp = 1.82 -----------------------------(answer)

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