A 70.0-kg grindstone is a solid disk 0.530m in diameter. You press an ax down on...

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Physics

A 70.0-kg grindstone is a solid disk 0.530m in diameter. Youpress an ax down on the rim with a normal force of 160N(Figure 1) . Thecoefficient of kinetic friction between the blade and the stone is0.60, and there is a constant friction torque of 6.50N?m betweenthe axle of the stone and its bearings.

A.How much force must be applied tangentially at the end of acrank handle 0.500 m long to bring the stone from rest to 120rev/min in 8.00s ?

B.After the grindstone attains an angular speed of 120 rev/min,what tangential force at the end of the handle is needed tomaintain a constant angular speed of 120 rev/min?

C.How much time does it take the grindstone to come from 120rev/min to rest if it is acted on by the axle friction alone?

Answer & Explanation Solved by verified expert
4.3 Ratings (720 Votes)
Let m 700 kg be the mass of the grindstone r 0265 m be its radius P 160 N be the normal force from the axe u 060 be the coefficient of friction between the axe and the stone F 650    See Answer
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