A 65.0 mL solution of 0.118 M potassium alaninate (H2NC2H5CO2K) is titrated with 0.118 M HCl....

90.2K

Verified Solution

Question

Chemistry

A 65.0 mL solution of 0.118 M potassium alaninate (H2NC2H5CO2K)is titrated with 0.118 M HCl. The pKa values for the amino acidalanine are 2.344 (pKa1) and 9.868 (pKa2), which correspond to thecarboxylic acid and amino groups, respectively.

a) Calculate the pH at the first equivalence point.

b) Calculate the pH at the second equivalence point.

Answer & Explanation Solved by verified expert
4.3 Ratings (922 Votes)
a at first equivalence point pH 12 pka1 pka2 hence pH 12 23449868 61 b at 2nd equivalence point we have H2NC2H5CO2K aq 2H aq 3HNC2H5CO2H aq H2NC2H5CO2K moles M x V    See Answer
Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students