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A 50.0-mL solution containing Ni2+ and Zn2+ was treated with 25.0 mL of 0.0452 M EDTA...

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Chemistry

A 50.0-mL solution containing Ni2+ and Zn2+ wastreated with 25.0 mL of 0.0452 M EDTA to bind all the metal. Theexcess unreated EDTA required 12.4 mL of 0.0123 M Mg2+ for completereaction. An excess of the reagent 2,3-dimercapto-1-propanol wasthen added to displace the EDTA from zinc. Another 29.2 mL of Mg2+was required for reaction with the liberated EDTA. Calculate themolarity of Ni2+ and Zn2+ in the original solution

Answer & Explanation Solved by verified expert
4.4 Ratings (590 Votes)
Molarity of EDTA added 00452M 00452 molL Volume added 25 mL 0025 L Moles of EDTA Molarity Volume 00452 M0025 L 000113 moles EDTA in excess moles of Mg2 required    See Answer
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