A 30.0-mL sample of 0.165 M propanoic acid is titrated with 0.300 MKOH. A)Calculate the pH at...

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Chemistry

A 30.0-mL sample of 0.165 M propanoic acid is titrated with0.300 MKOH.
A)Calculate the pH at 0 mL of added base. D)Calculate the pH atthe equivalence point. G)Calculate the pH at 25 mL of addedbase.
B)Calculate the pH at 5 mL of added base. E)Calculate the pH atone-half of the equivalence point.
C)Calculate the pH at 10 mL of added base. F)Calculate the pH at20 mL of added base.

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3.9 Ratings (536 Votes)

The reaction can be expressed as follows Pr Propyl group PrOOH KOH PrOOK H2O The information we have V PrOOH 300mL 003L M PrOOH 0165 M M KOH 0300M pKa PrOOH 487 from tables Before we start were going to need the number of moles of PrOOH present in the sample for this use the formula M nV n MV n 0165M003L n 000495 moles PrOOH A Calculate the pH at 0 mL of added base For this we can use the formula pH logKaC12 Where Ka 10pKa and C initial See Answer

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