A 30.0- mL sample of 0.165 M propanoic acid is titrated with 0.300 MKOH . Part...

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Chemistry

A 30.0- mL sample of 0.165 M propanoic acid is titrated with0.300 MKOH . Part A Calculate the pH at 0 mL of added base. Part BCalculate the pH at 5 mL of added base. Part C Calculate the pH at10 mL of added base. Part D Calculate the pH at the equivalencepoint. Part E Calculate the pH at one-half of the equivalencepoint. Part F Calculate the pH at 20 mL of added base. Part GCalculate the pH at 25 mL of added base.

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pKa of propanoic acid CH3CH2COOH is 487 Represent propanoic acid as HA Part A Consider the dissociation of Haas below HA aq H aq Aaq initial 0165 0 0 change x x x equilibrium 0165 x x x Acid dissociation constant Ka HAHA xx0165 x Given pKa 487 Ka 10487 1349105 Therefore Ka x20165 x 1349105 x20165 x Make an assumption x is much smaller than 0165 so that 0165 x 0165 therefore 1349105 x20165 x2 222585106 x 1492103 Therefore H 1492103 M and pH log H See Answer

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