A 0.43-kilogram soccer ball sits on the grass. The coefficient of static friction betweenthe soccer...

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A 0.43-kilogram soccer ball sits on the grass. The coefficient of static friction betweenthe soccer ball and the grass is 0.4. A players kicks the ball horizontally, resulting in aninitial acceleration of 65 m/s horizontally.What was the force of static friction applied to the ball at the time of the kick?.4(.43) 10 1.73 f=1.72 NWhat was the force of the kick?F=m.a/ (43)(65m) = 27.950 F=27.95NImagine the situation was on a different surface like artificial turf, and the coefficient ofstatic friction changed to 0.45. To get the same acceleration, how much more forcewould the kick need?

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