5.0 mL 1.0 M NaOAc + 28.0 mL 1.0 M HOAc pH= 3.68 Calculations: 1. [H+] =? 2. [OAc-]=? 3....

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Chemistry

5.0 mL 1.0 M NaOAc + 28.0 mL 1.0 M HOAc

pH= 3.68

Calculations:

1. [H+] =?

2. [OAc-]=?

3. [HOAc]=?

4. Ka=?

Answer & Explanation Solved by verified expert
4.1 Ratings (701 Votes)
Given that 50 mL 10 M NaOAc 280 mL 10 M HOAc and pH 368 Moles of NaOAc molarity x volume in Litres 10 M x 0005 L 0005 moles    See Answer
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