3) A car turning in a circle is acceleratring in the centripetal direction, even if the speed...

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Physics

3)

A car turning in a circle is acceleratring in the centripetaldirection, even if the speed is constant. This centripetalacceleration is the cause of a radially inward directed net force.On a level road this net force is the friction force acting fromthe road on the tires. You already looked at examples for this.

On racetracks and also highway turns the reliance on frictioncan be reduced by \"banking\" the road. This also reduces the risk ofthe vehicle to roll over. The picture shows two cars and a bus inan extremely banked turn at the Mercedes test track.

Draw a free-body diagram for a car in a banked curve. Then findan expression for the speed at which a car can negotiate the turnwithout any friction in the radial direction (f=0).

Calculate that speed (in mph) for a 47 m radius turn that isbanked by 5 degrees.

4)

You just should have already derived an expression for the\"frictionless\" speed of a car in a banked turn. Now assume that thecoefficient of friction is us. Find anexpression for the maximum speed at which a car can drive through aturn with radius R and banking angle theta.

Evaluate your answer: test whether in the two limiting cases of\"no friction\" and \"level road\" your answer will turn into the tworesults you already have derived for these cases.

Below answer with the maximum speed (in mph) for a turn withradius 126 m, banking angle 10 degree, and coefficient of staticfriction 0.71.

Please help I have tried so many times I'm almost out oftries!

Answer & Explanation Solved by verified expert
4.2 Ratings (834 Votes)
3 We have to derive an expression for the speed V on thebanked curved path of radius R and angle Please refer to the attached free body diagram 1The forces in the vertical directionN cos mgN mg cos 1In the horizontal directionFnet N sin putting    See Answer
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