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  3. 2 the second integration by parts step 1 has shown

2 The second integration by parts Step 1 has shown that 1 4 e s...

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Calculus

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2 The second integration by parts Step 1 has shown that 1 4 e s sin 5x dx e cos 5x The integral on the right is not much different than the one you started with Let s try using integration by parts again on the integral on the right Solution Fill in the table below with the appropriate terms for setting up the integration by parts for the integral Step 3 Putting it all together In Step 1 you found and in Step 2 you found that U du ez sin 5x dx 1 5 e s cos 5x da 0 Now substitute all of this into the Integration by Parts formula giving e cos 5x dx 0 10 dx V 1 fe co dv dx e sin 5x dx e cos 5x fe el cos 5x dx cos 5x dx e cos bx dx e sin 52 e sin 52 da 5 Now substitute the step 2 result into the result from step 1 4 Setz 42 cos 52 e sin 5x fe 5 5 e sin 5x da This gives you the term e sin 52 dar on both sides of the equation Now solve this equation fets sin 52 dz Be careful of the parentheses for e sin 5x dx 0

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