1) You are interested in testing if there is a difference inweight-loss between 3 popular diet types; low calorie, low fat andlow carb. Participants are randomly assigned one of the threegroups or a control group. The control group will be told that areparticipating in a weight-loss study, but will not be following anyparticular diet. This is to study the placebo effect, weight-lossfrom just participating in the study.
At the start of the study,each participant's weight is recorded inpounds. After 8 weeks they are weighed again, and the weightdifference is recorded. A positive value represents a weight losswhile a negative value represents a weight gain. Test at 5%significance.
Low Calorie | Low Fat | Low Carb | Control |
---|
10.2 | 6.2 | 2.9 | 2.7 |
7.3 | 6 | 2.8 | 3.4 |
4.7 | 3.4 | 4.4 | 0.6 |
9 | 2 | 5.6 | -1.4 |
2.7 | 3 | 3 | 0.7 |
What is the factor variable? Select an answer Diet Type PoundsLost
What is the response variable? Select an answer Pounds Lost DietType
Test Statistic:
P-Value:
Decision Rule: Select an answer Accept the Null Reject the NullFail to Reject the Null
Did Something Significant Happen? Select an answer NothingSignificant Happened Significance Happened
There Select an answer is is not  to conclude Select ananswer The true average weight loss is the same for all diet types.At least one true average weight loss is different between the diettypes.
2) Is a statistics class' delivery type a factor in how wellstudents do on the final exam? The table below shows the averagepercent on final exams from several randomly selected classes thatused the different delivery types.
Hybrid | Online | Face-to-Face |
---|
70 | 58 | 80 |
85 | 63 | 77 |
62 | 72 | 87 |
82 | 80 | 100 |
66 | 92 | 89 |
78 | 87 | 94 |
71 | 64 | 79 |
57 | | |
Assume that all distributions are normal, the three populationstandard deviations are all the same, and the data was collectedindependently and randomly. Use a level of significance ofα=0.1α=0.1.
- For this study, we should use Select an answer χ²GOF-Test2-PropZTest TInterval 2-PropZInt 2-SampTTest 1-PropZTest 1-PropZIntT-Test 2-SampTInt χ²-Test ANOVA
- Your friend Esmeralda helped you with the null and alternativehypotheses...
H0: μ1=μ2=μ3H0: μ1=μ2=μ3
H1:H1: At least one of the mean is different from theothers.
- The test-statistic for this data = (Please show your answer to3 decimal places.)
- The p-value for this sample =Â Â (Please show youranswer to 4 decimal places.)
- The p-value is Select an answer greater than alpha less than(or equal to) alpha  αα
- Base on this, we should Select an answer reject the nullhypothesis fail to reject the null hypothesis accept the nullhypothesis  hypothesis
- As such, the final conclusion is that...
- There is sufficient evidence to support the claim that coursedelivery type is a factor in final exam score.
- There is insufficient evidence to support the claim that coursedelivery type is a factor in final exam score.