(a)
      The acceleration
is  a  =  0.215 m
/s2
       The radius of the
disk is,
                    Â
r = diameter / 2
                       Â
= 19.5 cm /2
                       Â
= 0.0975 m
Hence, the angular acceleration is,
                              ?  Â
=Â Â a / r
                                     =
0.215 m/s2/ 0.0975 m
                                   Â
= 2.205 rad/s2
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(b)
The required tension can be calculated as,
            Â
T = m a
               Â
= 0.195 kg * 2.205 rad/s2
               Â
= 0.4299 N.m
               Â
= 0.43 N.m