Your acid has a pka of 6.45 and a concentration of 0.079M. You are given 40.8mL...

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Your acid has a pka of 6.45 and a concentration of 0.079M. Youare given 40.8mL of this acid, what is the pH of this initialsolution? Calculate the pH of the solution after adding 6.8, 15.3,27.9, and 33.7 mL of 0.100M NaOH. At the equivalence point, whatvolume of base is added and what is the pH?

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3.9 Ratings (520 Votes)

we know that pKa log Ka 645 log Ka Ka 3548 x 107 for weak acids H sqrt Ka x C so H sqrt 3548 x 107 x 0079 H 1674 x 104 now pH log H so pH log 1674 x 104 so pH 3776 so initially the pH is 3776 2 now 68 ml of NaOH is added we know that moles conc x volume L so moles of NaOH added 01 x 68 x 103 068 x 103 moles of acid 0079 x 408 x 103 32232 x 103 now the reaction is HA NaOH NaA H20 we can see that moles of HA reacted moles of NaOH added 068 x 103 so moles of HA remaining 32232 x 103 068 x 103 25432 x 103 moles of NaA See Answer

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