You want to make 750.00 mL of a 0.9550 M aqueous solution of Cr(NO3)2. You have...

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You want to make 750.00 mL of a 0.9550 M aqueous solution ofCr(NO3)2. You have available in lab a bottle of pure Cr(NO3)2 ∙ 6H2O (s), a bottle of 1.672 M Cr(NO3)2 solution and a bottle of0.5005 M Cr(NO3)2.

a) How many grams of the Cr(NO3)2 ∙ 6 H2O (s) would you need touse to prepare the desired solution?

b) How many mL of the 1.672 M Cr(NO3)2 solution would you needto use to prepare the desired solution?

c) Describe how you could use the 0.5005 M Cr(NO3)2 solution toprepare the desired solution.

Answer & Explanation Solved by verified expert
3.9 Ratings (606 Votes)
a How many grams of the CrNO32 6 H2O s would you need to use to prepare the desired solution First calculate the moles of CrNO32 in 09550 M Number of moles    See Answer
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