You may need to use the appropriate technology to answer thisquestion.

The following data are from a completely randomized design.

	Treatment
A	B	C
	161	143	126
143	157	121
164	125	137
144	141	139
149	137	151
169	143	124
Sample mean	155	141	133
Sample variance	122.8	107.2	130.0

(a)

Compute the sum of squares between treatments.

(b)

Compute the mean square between treatments.

(c)

Compute the sum of squares due to error.

(d)

Compute the mean square due to error. (Round your answer to twodecimal places.)

(e)

Set up the ANOVA table for this problem. (Round your values forMSE and F to two decimal places, and your p-valueto four decimal places.)

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F	p-value
Treatments
Error
Total

(f)

At the α = 0.05 level of significance, test whether themeans for the three treatments are equal.

State the null and alternative hypotheses.

H₀: μ_A =μ_B = μ_C
H_a: μ_A ≠μ_B ≠μ_CH₀: Not all thepopulation means are equal.
H_a: μ_A =μ_B =μ_C    H₀:μ_A = μ_B =μ_C
H_a: Not all the population means areequal.H₀: At least two of the population meansare equal.
H_a: At least two of the population means aredifferent.H₀: μ_A ≠μ_B ≠ μ_C
H_a: μ_A =μ_B = μ_C

Find the value of the test statistic. (Round your answer to twodecimal places.)

Find the p-value. (Round your answer to four decimalplaces.)

p-value =

State your conclusion.

Do not reject H₀. There is sufficientevidence to conclude that the means for the three treatments arenot equal.Reject H₀. There is sufficientevidence to conclude that the means for the three treatments arenot equal.    Do not rejectH₀. There is not sufficient evidence toconclude that the means for the three treatments are notequal.Reject H₀. There is not sufficientevidence to conclude that the means for the three treatments arenot equal.