You have three genes on the same chromosome - A, B and C. Eachgene has two alleles in a dominant/recessive relationship. Forthese genes the homozygous recessive has the mutant phenotype forthat trait, the dominant phenotype = wild type for that trait.
- allele A is dominant to a; phenotype a = mutant for trait a;phenotype A = wild type for trait A
- allele B is dominant to b; phenotype b = mutant for trait b;phenotype B = wild type for trait B
- allele C is dominant to c; phenotype c = mutant for trait c;phenotype C = wild type for trait C
Note: phenotypes can be represented by singleletters. For example phenotype A = genotypes Aa orAA; phenotype a = genotype aa. Assume thatphenotype ab =mutant phenotype for traits a andb, and wild type phenotype for traitC.
You cross an individual heterozygote for all three genes, withan individual who is homozygote recessive for all three. Out of10,000 offspring you get the following phenotypes and amounts:
- phenotype a - 98
- phenotype b - 150
- phenotype c - 4751
- phenotype ab - 4749
- phenotype ac - 147
- phenotype bc - 99
- phenotype abc - 3
- wild type - 3
Use this information to answer the following questions.
Based on the information given and your answer to the previousquestions, what was the genotype of the heterozygous parent, in thecorrect order?
Select one:
a. BAc/baC
b. ABC/abc
c. AcB/aCb
d. ACB/acb
e. ABc/abC
