You have three genes on the same chromosome - A, B and C. Each gene has...

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Biology

You have three genes on the same chromosome - A, B and C. Eachgene has two alleles in a dominant/recessive relationship. Forthese genes the homozygous recessive has the mutant phenotype forthat trait, the dominant phenotype = wild type for that trait.

  • allele A is dominant to a; phenotype a = mutant for trait a;phenotype A = wild type for trait A
  • allele B is dominant to b; phenotype b = mutant for trait b;phenotype B = wild type for trait B
  • allele C is dominant to c; phenotype c = mutant for trait c;phenotype C = wild type for trait C

Note: phenotypes can be represented by singleletters. For example phenotype A = genotypes Aa orAA; phenotype a = genotype aa. Assume thatphenotype ab =mutant phenotype for traits a andb, and wild type phenotype for traitC.

You cross an individual heterozygote for all three genes, withan individual who is homozygote recessive for all three. Out of10,000 offspring you get the following phenotypes and amounts:

  • phenotype a - 98
  • phenotype b - 150
  • phenotype c - 4751
  • phenotype ab - 4749
  • phenotype ac - 147
  • phenotype bc - 99
  • phenotype abc - 3
  • wild type - 3

Use this information to answer the following questions.

For each phenotype determine if the number of offspring you areobserving is greater or less than you'd expect if all three genesare sorting independently (expectation = independentassortment).

Use the information at the top of this page to choose thecorrect answer.

For phenotype a there are ( less/more) offspringobserved than expected.


For phenotype b there are ( less/more) offspring observedthan expected.


For phenotype c there are ( less/more) offspring observedthan expected.


For phenotype ab there are ( less/more) offspring observedthan expected.


For phenotype ac there are (less/more) offspring observedthan expected.


For phenotype bc there are ( less/more) offspring observedthan expected.


For phenotype abc there are ( less/more) offspring observedthan expected.


For wild type there are ( less/more) offspring observedthan expected.

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Based on the information given and your answer to the previousquestions, what was the genotype of the heterozygous parent, in thecorrect order?

Select one:

a. BAc/baC

b. ACB/acb

c. ABc/abC

d. AcB/aCb

e. ABC/abc

Clear my choice

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Given the information at the top of the page, determine therecombination frequency for A-C. Show your workhere!

Note: You will choose the correct answer in the question below(multiple choice). This is for you to show your work.

You can show your work by typing out the math (fractions, % ordecimals; can use any format you like) or explaining how you foundthe answer in words, or a combination of both. Basically anydescription/showing of your work even if your answer is wrong = 2marks.

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Given the information at the top of the page, what is therecombination frequency for A-C? Frequency is given as a numberfrom 0 to 1.

Select one:

a. 0.03

b. 0.1

c. 0.02

d. 0.05

e. 0.015

Answer & Explanation Solved by verified expert
3.8 Ratings (612 Votes)
10 Trihybrid testcross ratio would be 11111111 It means that each phenotype would be an equal number ie 100008 1250 phenotype a 98 observed 1250 phenotype b 150 observed 1250 phenotype c 4751 observed 1250 phenotype ab 4749 observed 1250 phenotype ac 147 observed 1250 phenotype bc 99 observed 1250 phenotype abc 3 observed 1250 wild type 3 observed 1250 For phenotype a there are less offspring observed    See Answer
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