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You have 0.4mL of acetic acid and 0.4mL of isoamyl alcohol for the experiment. Which is...

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Chemistry

You have 0.4mL of acetic acid and 0.4mL of isoamyl alcohol forthe experiment. Which is the limiting reactant?

Answer & Explanation Solved by verified expert
4.0 Ratings (567 Votes)

acetic acid mass = volume x density       

                  = 0.4 ml x 1.05 g/ml

          = 0.42 g

acetic acid moles = mass / Molar mass of acetic acid

           = 0.42 g / ( 60.05 g/mol)   = 0.007

isoamyl alcohol mass = vol x density

            = 0.4 ml x 0.81 g/ml =0.324 g

isoamyl alcohol moles = mass / molar mass of it

             = 0.324 g / 88 g/mol

      = 0.0037

acetic acid and isoamyl alcohol react in 1:1 ratio

since relatively isoamyl alcohol is less the liming reagent is isoamyl alcohol

( densities and molar mass values taken from web)
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