X ~ ( Mean, 2.15) ( Suppose we do not have information of Mean of the...

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X ~ ( Mean, 2.15) ( Suppose we do not have information of Meanof the population) Question1-----------------------------------------------------------------------------Use calculator go to math---> PRB-------> random sample 1. Pick one (only-one) sample size of 5 (As we did in lab 2) calculate Mean of this sample and use the S.D. = 2.15/ sqrt(5) Calculate EBM **** Find C.I. for mean at 95% C.L. 2. Repeat thesame process for n=10 and n = 20 3. Study what happened toConfidence Interval when we increased the sample size. Question2-------------------------------------------------------------------------------------------------4. * Find C.I. For n=20 for C.L. 90% ** Study what happened toConfidence Interval when we increased and C.L. from 90% to 95%Question3----------------------------------------------------------------------------------------From the previous lab we know mean for recipe data was 3.57. Writea comment about what you notice in Question 1 and Question 2

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1 TRADITIONAL METHOD given that sample mean x 357 standard deviation s 215 sample size n 5 I stanadard error sd sqrtn where sd standard deviation n sample size standard error 215 sqrt 5 0962 II margin of error t 2 stanadard error where ta2 ttable value level of significance 005 from standard normal table two tailed value of t 2 with n1 4 df is 2776 margin of error 2776 0962 2669 III CI x margin of error confidence interval 357 2669 0901 6239 DIRECT METHOD given that sample mean x 357 standard deviation s 215 sample size n 5 level of significance 005 from standard normal table two tailed value of t 2 with n1 4 df is 2776 we use CI x t a2 sd Sqrtn where x mean sd standard deviation a 1 confidence level100 ta2 ttable value CI confidence interval confidence interval 357 t a2 215 Sqrt 5 3572776 0962 3572776 0962 0901 6239 interpretations 1 we are 95 sure that the interval 0901 6239 See Answer

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