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A mass weighing 8 pounds stretches a spring 2 feet. At t=0 the...
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A mass weighing 8 pounds stretches a spring 2 feet. At t=0 the massis released from a point 2 feet above the equilibrium position witha downward velocity of 4 (ft/s), determine the motion of themass.
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HelloAccording to Hookes law if we stretch a spring bydisplacing its free end by then the restoring force is set up in opposite direction toovercome stretching which is opposite direction to thedisplacementIf we dont concern the direction then magnitude ofrestoring force So removing proportionality yields Now see the figure belowWhen mass is not placed on the spring and spring ismassless
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