Will a precipitate form if 100 0 mL of 2 5 103M Cd(NO3)2 and75 0 mL o...

Will a precipitate form if 100.0 mL of 2.5 Ã— 10âˆ’3M Cd(NO3)2 and 75.0 mL of...

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Will a precipitate form if 100.0 mL of 2.5 Ã— 10âˆ’3M Cd(NO3)2 and75.0 mL of 0.0500 M NaOH are mixed at 25Â°C? Calculate theconcentration of cadmium ion in solution at equilibrium after thetwo solutions are mixed. (Ksp is 7.2 Ã— 10âˆ’15 for Cd(OH)2 at25Â°C)

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4.4 Ratings (700 Votes)

moles of Cd(NO3)2 = 100 x 2.5 x 10^-3 / 1000 = 2.5 x 10^-4

moles of NaOH = 75 x 0.05/1000 = 3.75 x 10^-3

Cd(NO3)2Â Â Â Â Â +Â Â Â Â 2 NaOH ---------------------> Cd(OH)2 + 2NaNO3

2.5 x 10^-4Â Â Â Â Â Â Â Â 3.75 x 10^-3Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2.5 x 10^-4

concentration of Cd(OH)2 = moles / total volume

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 2.5 x 10^-4 / (0.100 + 0.075)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.43 x 10^-3 M

[OH-] concentration = 2 x 1.43 x 10^-3 = 2.86 x 10^-3 M

Cd(OH)2 --------------------> Cd+2 + 2 OH-

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â SÂ Â Â Â Â Â Â Â Â 2.86 x 10^-3

Ksp = [Cd+2][OH-]^2

7.2 Ã— 10^âˆ’15 = S x (2.86 x 10^-3)^2

S = 8.82 x 10^-10 M

[Cd+2] = 8.82 x 10^-10 M

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Will a precipitate form if 100.0 mL of 2.5 Ã— 10âˆ’3M Cd(NO3)2 and 75.0 mL of...

Free

60.1K

Verified Solution

Question

Chemistry

Will a precipitate form if 100.0 mL of 2.5 Ã— 10âˆ’3M Cd(NO3)2 and75.0 mL of 0.0500 M NaOH are mixed at 25Â°C? Calculate theconcentration of cadmium ion in solution at equilibrium after thetwo solutions are mixed. (Ksp is 7.2 Ã— 10âˆ’15 for Cd(OH)2 at25Â°C)

Answer & Explanation Solved by verified expert

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